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33x^2-420x-132=0
a = 33; b = -420; c = -132;
Δ = b2-4ac
Δ = -4202-4·33·(-132)
Δ = 193824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{193824}=\sqrt{144*1346}=\sqrt{144}*\sqrt{1346}=12\sqrt{1346}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-420)-12\sqrt{1346}}{2*33}=\frac{420-12\sqrt{1346}}{66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-420)+12\sqrt{1346}}{2*33}=\frac{420+12\sqrt{1346}}{66} $
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